Standing waves are produced by the superposition of two waves, y1=0.05sin(3πt−2x) and y2=0.05sin(3πt+2x), where x and y are expressed in metres and t is in seconds. What is the amplitude of a particle at x=0.5 m? Given cos57.3∘=0.54.

Standing waves are produced by the superposition of two waves, y1=0.05

1.	Standing waves are produced by the superposition of two waves, y1=0.05sin(3πt−2x) and y2=0.05sin(3πt+2x), where x and y are expressed in metres and t is in seconds. What is the amplitude of a particle at x=0.5 m? Given cos57.3∘=0.54.
Answer» Standing waves are produced by the superposition of two waves, $y_{1} = 0.05 sin (3 π t - 2 x)$ and $y_{2} = 0.05 sin (3 π t + 2 x)$ , where $x$ and $y$ are expressed in metres and $t$ is in seconds. What is the amplitude of a particle at $x = 0.5 m$ ? Given $cos {57.3}^{\circ} = 0.54$ .

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Standing waves are produced by the superposition of two waves, y1=0.05sin(3πt−2x) and y2=0.05sin(3πt+2x), where x and y are expressed in metres and t is in seconds. What is the amplitude of a particle at x=0.5 m? Given cos57.3∘=0.54.

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