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Standard molar enthalpy of formation, ΔfH⊖ is just a special case of enthalpy of reaction, ΔrH⊖ . Is the ΔrH⊖ for the following reaction same as ΔfH⊖ ? Give reason for your answer. Ca0(s)+CO2(g)→CaCO3(s);ΔfH⊖=−178.3 kJ mol−1

Answer»

Standard molar enthalpy of formation, ΔfH is just a special case of enthalpy of reaction, ΔrH . Is the ΔrH for the following reaction same as ΔfH ? Give reason for your answer.
Ca0(s)+CO2(g)CaCO3(s);ΔfH=178.3 kJ mol1



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