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Standard Free Energy and Equilibrium constant: The change in free energy for a reaction taking place between gaseous reactants and products represented by general equation.ΔG=ΔG∘+R T lnQP the condition for a system to be at equilibrium is thatΔG=0 and Qp=KPThus at equilibriumΔG∘=−R T lnKPNote: In the reaction, where all gaseous reactants and products; K represents KP, we may conclude that for standard reactions, i.e., at 1 M or 1 atmWhen ΔG∘=−ve or K>1: forward reaction is feasibleΔG∘=+ve or K<1: reverse reaction is feasibleΔG∘=0 or K=1: reaction is at equilibrium (very rare)For the equilibrium NiO(s)+CO(g)⇌Ni(s)+CO2(g),ΔG∘(J Mol−1)=−20700−11.97T.. Calculate the temperature at which the product gases at equilibrium at 1 atm will conatin 400 ppm of carbon monoxide.

Answer»

Standard Free Energy and Equilibrium constant: The change in free energy for a reaction taking place between gaseous reactants and products represented by general equation.

ΔG=ΔG∘+R T lnQP the condition for a system to be at equilibrium is that

ΔG=0 and Qp=KP

Thus at equilibrium

ΔG∘=−R T lnKP

Note: In the reaction, where all gaseous reactants and products; K represents KP, we may conclude that for standard reactions, i.e., at 1 M or 1 atm

When ΔG∘=−ve or K>1: forward reaction is feasible

ΔG∘=+ve or K<1: reverse reaction is feasible

ΔG∘=0 or K=1: reaction is at equilibrium (very rare)

For the equilibrium NiO(s)+CO(g)⇌Ni(s)+CO2(g),ΔG∘(J Mol−1)=−20700−11.97T.. Calculate the temperature at which the product gases at equilibrium at 1 atm will conatin 400 ppm of carbon monoxide.


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