St. XI10. Can two mumbers have 12 as their HCF and 512 as their LCM? J – InterviewSolution

1.	St. XI10. Can two mumbers have 12 as their HCF and 512 as their LCM? Justify your answer.vaceeditins 90P Digital
Answer» LCM×HCF= product of no12×512=product of no6144= product of no hcf= product of no/LCM = 6144/512=12LCM= product of no/HCF = 6144/12=512

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