1.

Square of (√5+√3/√5-√3)+square of(√5-√3/√5+√3)

Answer»

Step by STEP Explanation:-

( \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} } ) {}^{2}  + ( \frac{ \sqrt{5 }  -  \sqrt{3} }{ \sqrt{5}  +  \sqrt{3} } ) {}^{2}  \\  =  \frac{(\sqrt{5}  +  \sqrt{3}) {}^{2} }{(\sqrt{5}   -   \sqrt{3}) {}^{2} }  + \frac{(\sqrt{5}   -  \sqrt{3}) {}^{2} }{(\sqrt{5}    +  \sqrt{3}) {}^{2} } \\  =  \frac{5 + 2 \sqrt{15} + 3 }{5  -  2 \sqrt{15} + 3 }  + \frac{5  -  2 \sqrt{15} + 3 }{5   +   2 \sqrt{15} + 3 }  \\  =  \frac{8 + 2 \sqrt{15} }{8 - 2 \sqrt{15} }  +  \frac{8 - 2 \sqrt{15} }{8 + 2 \sqrt{15} }  \\  =  \frac{(8 + 2 \sqrt{15} ) {}^{2} + (8 - 2 \sqrt{15} ) {}^{2}  }{(8 - 2 \sqrt{15} )(8 + 2 \sqrt{15} )}  \\  =  \frac{(64 + 32 \sqrt{15}  + 60) + 64 - 32 \sqrt{15}  + 60}{64 - 60}  \\  =  \frac{124 + 32 \sqrt{15} + 124 - 32 \sqrt{15}  }{4}  \\  =  \frac{248}{4}  \\  = 62

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