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`(-sqrt3+ sqrt-2) (2 sqrt3 -i)` को `a + ib` के रूप में व्यक्त करो। |
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Answer» `(-sqrt3 + sqrt-2) (2 sqrt3 -i)` `= (-sqrt3 + sqrt2i) (2 sqrt3 -i)` `= (-sqrt3) (2 sqrt3) + (sqrt2i) (2 sqrt3) + sqrt3i - sqrt2i^(2)` `= -6 +2 sqrt6i + sqrt3i + sqrt2` `= (-6 + sqrt2) + sqrt3 (1 + 2 sqrt2)i` |
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