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sqrt(6-x)+sqrt(x-10)>0 |
| Answer» sqrt(6-x) + sqrt(x-10) >0on squaring....6-x + x-10 +2[sqrt(6x-60-x2+10x)] >0 (x2=square(x))-16 +2 sqrt(-x2+16x-60)>0on solving this equation.......we can get the answer i.e.(x-6)(-x+10)>sqr(8)(x-6)(-x+10)>64u can easily solve this.........\xa0 | |