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\(\sqrt[3]{(64/343)}\) = ?a) 4/9b) 4/7c) 8/7d) 8/21 |
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Answer» Firstly we have to find the prime factors of 64 64 = 2 × 2 × 2 × 2 × 2 × 2 And the prime factors of 343 343 = 7 × 7 × 7 = \(\sqrt[3]{64/343}\) = \(\sqrt[3]{(4 × 4 × 4/7 × 7 × 7)}\) = 4/7 ∴ 4/7 is the correct answer. |
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