1.

\(\sqrt[3]{(64/343)}\) = ?a) 4/9b) 4/7c) 8/7d) 8/21

Answer»

Firstly we have to find the prime factors of 64

64 = 2 × 2 × 2 × 2 × 2 × 2

And the prime factors of 343

343 = 7 × 7 × 7

= \(\sqrt[3]{64/343}\)

= \(\sqrt[3]{(4 × 4 × 4/7 × 7 × 7)}\)

= 4/7

∴ 4/7 is the correct answer.



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