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\sqrt { - 2 + 2 \sqrt { - 2 + 2 \sqrt { - 2 + \dots \infty } } } |
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Answer» suppose x=root(-2+2root(-2+2root(-2...)))so x=root(-2+2x)by taking squarex^2=-2+2xx^2-2x+2=0x=(2+root(4-8))/2 or (2-root(4-8))/2 =(2+2i)/2 (2-2i)/2 =1+i 1-i |
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