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Split 69 into 3 parts, which are in А.Р. and the product oftwo smaller parts is 483. |
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Answer» Let the first term of the AP be 'a'And the common difference be 'd'Since 69 split into 3 parts such that they form an AP.Let the three parts be (a - d), (a) and (a + d).Therefore,(a - d) + (a) + (a + d) = 693a = 69a = 23The product if two smaller parts = 483So,(a)× (a - d) = 48323× (23 - d) = 483⇒ 529 - 23d = 483⇒ - 23d = 483 - 529⇒ - 23 d = - 46⇒ d = 46/23⇒ d = 2Therefore,The 3 parts are 23 - 2 = 21 ;23and 23 + 2 = 25Hence the parts of the given AP are21, 23, 25 |
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