spindi ogradius2gmentofthecirde(Use,s314|NCERT EXEMPLARI7) A chord of

1.	spindi ogradius2gmentofthecirde(Use,s314\|NCERT EXEMPLARI7) A chord of a circle of radius 20 cm subtends an angle of 90Â° at the centre. Find the areaof the corresponding major segment of the circle. (Use Ď = 3.14)
Answer» r = 20cm¤ = 90°Area of sector = theta/360 * π * r2 = 90/360 * 22/7 * 20 * 20 = 1/4 * 22/7 * 20 * 20 = 2200/7314.2 cm2 Area of triangle = 1/2 * base * height = 1/2 * 20 20 (base and height both are r ) = 200 cm2 Area of minor segment = 314.2 - 200 = 114.2 cm2 major segment = area of circle - 114.2 = π r2- 114.2 =22/7 * 20 * 20 -114.2 = 1142 .94 cm2 hai

spindi ogradius2gmentofthecirde(Use,s314|NCERT EXEMPLARI7) A chord of a circle of radius 20 cm subtends an angle of 90Â° at the centre. Find the areaof the corresponding major segment of the circle. (Use Ď = 3.14)

Answer»

r = 20cm¤ = 90°Area of sector = theta/360 * π * r2

= 90/360 * 22/7 * 20 * 20

= 1/4 * 22/7 * 20 * 20

= 2200/7314.2 cm2

Area of triangle = 1/2 * base * height

= 1/2 * 20 *20 (base and height both are r ) = 200 cm2

Area of minor segment = 314.2 - 200 = 114.2 cm2

major segment = area of circle - 114.2

= π * r2- 114.2

=22/7 * 20 * 20 -114.2

= 1142 .94 cm2

hai