1.

Specific heat capacity at constant pressure and at constant volume for nitrogen are respectively 1040 Jkg ^(-1) K ^(-1) and 743 Kg ^(-1) K ^(-1).Calculate the universal gas constant ?[E.Q.]

Answer»

Solution :Specidic heat capacity at CONSTANT pressure `= C_(p) = 1040 Jkg ^(-1) K ^(-1)`
Specific heat capacity at constatn volume `= C_(V) = 743 Jkg ^(-1) K ^(-1)`
`C _(p) - C_(v)= r`
SINCE the mass of gas is 1 kg, r is used
`r = C _(p) - C _(v) = 1040 - 743 = 297 J kg ^(-1) K ^(-1)`
Molar mass of `N _(2) = 28 gm = 28 xx 10 ^(-3) kg`
`R = rM = 297 xx 28 xx 10 ^(-3) = 8.316 J MOL ^(-1) K ^(-)`


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