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Specific heat capacity at constant pressure and at constant volume for nitrogen are respectively 1040 Jkg ^(-1) K ^(-1) and 743 Kg ^(-1) K ^(-1).Calculate the universal gas constant ?[E.Q.] |
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Answer» Solution :Specidic heat capacity at CONSTANT pressure `= C_(p) = 1040 Jkg ^(-1) K ^(-1)` Specific heat capacity at constatn volume `= C_(V) = 743 Jkg ^(-1) K ^(-1)` `C _(p) - C_(v)= r` SINCE the mass of gas is 1 kg, r is used `r = C _(p) - C _(v) = 1040 - 743 = 297 J kg ^(-1) K ^(-1)` Molar mass of `N _(2) = 28 gm = 28 xx 10 ^(-3) kg` `R = rM = 297 xx 28 xx 10 ^(-3) = 8.316 J MOL ^(-1) K ^(-)` |
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