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Specific heat at constant pressure C_(p) for a diatomic gas at N.T.P. in the units of cal mole k is: |
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Answer» <P>`4 CDOT 95` `=(1)/(2) K.T.` `therefore` The energy of 1 molecule `=5xx(1)/(2) KT` `therefore` 1 mole of gas contians N molecules. `therefore` Total energy of 1 mole of diatomic gas `U=(N cdot 5)/(2) kT. =(5)/(2) RT" "[because k=(R)/(N)]` Since `C_(v) =(dU)/(dT)` `C_(v)=(5)/(2) R` `therefore C_(p) =C_(v) +R =(7)/(2) R=(7)/(2) xx1 cdot 98=6 cdot 93" cal mole"^(-1)k^(-1)` THUS, correct choice is (b). |
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