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Specific conductance of 0.1M HA is 3.75×10−4ohm−1cm−1. If λ∞ of HA is 250ohm−1cm2mol−1, then dissociation constant Ka of HA is

Answer»

Specific conductance of 0.1M HA is 3.75×10−4ohm−1cm−1. If λ∞ of HA is 250ohm−1cm2mol−1, then dissociation constant Ka of HA is



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