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Something yellow turbidity appears on passing `H_(2)S` gas even in the absence of the second group radicals. Theis happens becauseA. Sulphur is present in the mixture as an impurityB. The fourth group radicals are precipitated as sulphidesC. The `H_(2)S` is oxidized by some acid/Basic radicalsD. The third group radicals are precipitated |
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Answer» Correct Answer - C This is due to high concentration of S in the solution as a result yellow turbidity is obtained `H_(2)Sunderset("radicals")overset("oxidise")(rarr)S` |
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