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Solve x²+4ix-5=0 where i=√-1 |
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Answer» Answer:STEPS USING THE QUADRATIC FORMULA x 2 −4ix−5=0 All equations of the form ax 2 +bx+C=0 can be solved using the quadratic formula: 2a −b± b 2 −4ac
. The quadratic formula GIVES two solutions, ONE when ± is addition and one when it is subtraction. x 2 −4ix−5=0 This equation is in standard form: ax 2 +bx+c=0. SUBSTITUTE 1 for a, −4i for b, and −5 for c in the quadratic formula, 2a −b± b 2 −4ac
. x= 2 4i± (−4i) 2 −4(−5)
SQUARE −4i. x= 2 4i± −16−4(−5)
Multiply −4 times −5. x= 2 4i± −16+20
Add −16 to 20. x= 2 4i± 4
Take the square root of 4. x= 2 4i±2
Now solve the equation x= 2 4i±2 when ± is plus. Add 4i to 2. x= 2 2+4i
Divide 2+4i by 2. x=1+2i Now solve the equation x= 2 4i±2 when ± is minus. Subtract 2 from 4i. x= 2 −2+4i
Divide −2+4i by 2. x=−1+2i The equation is now solved. x=1+2i x=−1+2i Step-by-step explanation: |
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