Given X= a/bY = c/dRequired to find..(x-y)^2we KNOW that (a-b)^2 = a^2 - 2AB +b^2 in the same way (x-y)^2 =x^2 - 2xy + y^2 = 0subsitute x and y values (a/b)^2 - 2.(a/b).(c/d) + (c/d)^2 = 0a^2/b^2 -2.ac/BD + c^2/d^2 =0l.C.Ma^2×(d^2) - 2ac(bd) +c^2 × (b^2)---------------------------------------------- =0 b^2 × d^2(AD)^2 -2abcd + (CB)^2 = 0its in the form of (ad + cb)2
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