1.

solve x,root(8^0 + 2/3) = (3/5)^2-3x?

Answer»

root(8^0 + 2/3) = (3/5)^2-3x

(1 + 2/3)^1/2 = (5/3)^3x-2

(5/3)^1/2 = (5/3)^3x-2

1/2 = 3x - 2

3x = 1/2 + 2 = 5/2

x = 5/6



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