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solve x,root(8^0 + 2/3) = (3/5)^2-3x? |
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Answer» root(8^0 + 2/3) = (3/5)^2-3x (1 + 2/3)^1/2 = (5/3)^3x-2 (5/3)^1/2 = (5/3)^3x-2 1/2 = 3x - 2 3x = 1/2 + 2 = 5/2 x = 5/6 |
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