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Solve `x (dy)/(dx)sin(y/x)+x-ysin(y/x)=0` given `y(1)=pi/2`

Answer» `x(dy/dx)sin(y/x)+x-ysin(y/x) = 0`
Dividing given equation with `xsin(y/x)`
`=>dy/dx+1/sin(y/x)-y/x = 0`
Let `y/x = v`
Then, `y = vx =>dy/dx = v+x(dv)/dx`
So, given equation becomes,
`=>v+x(dv)/dx+1/sinv-v = 0`
`=> x(dv)/dx = -1/sinv`
`=> sinvdv = -dx/x`
Integrating both sides,
`=> int sinvdv = int -dx/x`
`=>-cos v = -ln x +c`
`=>-cos(y/x) = -ln x +c`
Now, we are given, `y(1) = pi/2`
So, putting `x = 1 and y = pi/2`
`=>-cos pi/2 = -ln(1) + c => c = 0`
So, our equation becomes,
`=>-cos(y/x) = -lnx`
`=>cos(y/x) = ln x`, which is the required solution.


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