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Solve `|x-3|+|x-2|=1.` |
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Answer» `|x-3|=|x-2|=1` `implies |x-3|+|x-2|=(3-x)+(x-2)` `implies x-3 le 0 " and " x-2 ge 0` `implies x le 3 " and " x ge 2` `implies 2 le x le 3` |
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