Solve |x|^2 - |x| + 4= 2x^2 - 3|x| +1

1.	Solve \|x\|^2 - \|x\| + 4= 2x^2 - 3\|x\| +1
Answer» Answer: $\|<klux>X</klux>\| {}^{2} - \|x\| + 4 = 2 \|x\| {}^{2} - <klux>3</klux> \|x\| + 1 \\ \|x\| {}^{2} - 2 \|x\| - 3 = 0 \\ \|x\| {}^{2} + \|x\| - 3 \|x\| - 3 = 0 \\ \|x\|( \|x\| + 1) - 3( \|x\| + 1) = 0 \\ \|x\| = - 1(not \: possible) \: or \: \|x\| = 3 \\ so \: x = 3 \: or \: x = - 3$ So possible values of x are 3 and - 3. Hope it HELPS

Answer»

Answer:

$|<klux>X</klux>| {}^{2} - |x| + 4 = 2 |x| {}^{2} - <klux>3</klux> |x| + 1 \\ |x| {}^{2} - 2 |x| - 3 = 0 \\ |x| {}^{2} + |x| - 3 |x| - 3 = 0 \\ |x|( |x| + 1) - 3( |x| + 1) = 0 \\ |x| = - 1(not \: possible) \: or \: |x| = 3 \\ so \: x = 3 \: or \: x = - 3$

So possible values of x are 3 and - 3.

Hope it HELPS

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Solve |x|^2 - |x| + 4= 2x^2 - 3|x| +1

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