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Solve (x+2) (x-3) (x-7) (x-2) +64Polynomial C.T.2.B type 2 Sum |
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Answer» ong>Answer: This is an easy step—easy to overlook, unfortunately. If you have a polynomial equation, put all terms on one side and 0 on the other. And whether it’s a factoring problem or an equation to solve, put your polynomial in standard form, from highest to lowest power. For instance, you cannot solve this equation in this form: x³ + 6x² + 12x = −8 You must change it to this form: x³ + 6x² + 12x + 8 = 0 Also make sure you have simplified, by factoring out any COMMON factors. This may include factoring out a −1 so that the highest power has a POSITIVE coefficient. Example: to factor 7 − 6x − 15x² − 2x³ begin by putting it in standard form: −2x³ − 15x² − 6x + 7 and then factor out the −1 −(2x³ + 15x² + 6x − 7) or (−1)(2x³ + 15x² + 6x − 7) If you’re solving an equation, you can throw away any common constant factor. But if you’re factoring a polynomial, you must keep the common factor. Example: To solve 8x² + 16x + 8 = 0, you can divide LEFT and right by the common factor 8. The equation x² + 2x + 1 = 0 has the same roots as the original equation. Example: To factor 8x² + 16x + 8 , you recognize the common factor of 8 and rewrite the polynomial as 8(x² + 2x + 1), which is identical to the original polynomial. (While it’s true that you will focus your further factoring efforts on x² + 2x + 1, it WOULD be an error to write that the original polynomial equals x² + 2x + 1.) |
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