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solve using the quadratic formula |
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Answer» \(\frac{2x}{x-4}+\frac{2x-5}{x-3}=\frac{25}3\) ⇒ 6x(x - 3) + 3(2x - 5) (x - 4) = 25 (x - 3)(x - 4) ⇒ 6x2 - 18x + 6x2 - 39x + 60 = 25x2 - 175x + 300 ⇒ 25x2 - 12x2 - 175x + 57x + 240 = 0 ⇒ 13x2 - 118x + 240 = 0 ⇒ x = \(\frac{118\pm\sqrt{13924-12480}}{26}\) = \(\frac{118\pm\sqrt{1444}}{26}\) \(=\frac{118\pm38}{26}\) = \(\frac{118+38}{26}\) or \(\frac{118-38}{26}\) = 6 or 40/13 |
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