solve using substitution method : 0.2x+0.3y=1.3 and 0.4x+ 0.5y=2.3. pa

1.	solve using substitution method : 0.2x+0.3y=1.3 and 0.4x+ 0.5y=2.3. pair of linear equation. ch3 class 10 ncert
Answer» ANSWER: X = 2 and y = 3 Step-by-step explanation: Given : $0.2x+0.3y=1.3$ $0.4x+ 0.5y=2.3$ To Find : solve USING substitution method SOLUTION : $0.2x+0.3y=1.3$ -----1 $0.4x+ 0.5y=2.3$ ------2 Substitute the value of x from 1 in 2 $0.4(\frac{1.3 - 0.3 y}{0.2})+ 0.5y=2.3$ $y=3$ $0.2x+0.3(3)=1.3$ $0.2x=1.3-0.9$ $x=\frac{1.3-0.9}{0.2}$ $x=2$ So, x = 2 and y = 3