1.

Solve using any thing 4x+3y=65 and x+2y=35​

Answer»

Suppose we use ELIMINATION method to get answer: 4x+3y=65 is equation 1 and X +2Y =35 is equation 2.
(4x+3y=65) x 1
(x+2y=35) x 4
So it forms 4x+3y=65 and 4x+8y=140

Now we should Subtract EQ 2 from eq1

4x+3y=65
4x+8y=140
——————
-5y= -75
So,y=15

Putting y=15 in eq2
So,x+2y=35
x+2(15)=35
x+30=35
x=35-30
Therefore x=5
You can ALSO put in eq 2 and the same answer u will get it



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