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Solve this questionPlease explain Please answer it correctly I will mark you as brainlist Please answer it very fast ​

Answer»

\frac{<klux>X</klux>}{<klux>5</klux>} + \frac{28}{x + 2} = 5

\frac{x(x + 2) + 28 \times 5}{5(x + 2)} = 5 \\ \\ \frac{ {x}^{2} + 2x + 140}{5x + 10} = 5 \\ \\ {x}^{2} + 2x + 140 = 25x + 50 \\ \\ {x}^{2} + 2x + 140 - 25x - 50 = 0 \\ \\ {x}^{2} - 23x + 90 = 0 \\ \\ {x}^{2} + 5x + 18x + 90 = 0 \\ \\ x(x + 5) + <klux>18</klux>(x + 5) = 0 \\ \\ (x + 5)(x + 18) = 0

Here x = -5 and x = -18.

The REQUIRED ROOTS are -5 and -18.


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