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Answer:

AB = AB

AD = BC

AC = BD

∠DAB = ∠CBA

∠DBA = ∠CAB

∠ADB = ∠BCA

Step-by-step EXPLANATION:

We have,

ΔDAB and ΔCAB

Now,

In ΔDAB and ΔCAB,

∠DAB = 45° + 30° = 75°

∠CBA = 45° + 30° = 75°

So,

∠DAB = ∠CBA [Angle]

AB = AB [Common Side]

∠DBA = ∠CAB = 30° [Angle]

Hence,

ΔDAB ≅ ΔCBA (By A.S.A. Congruency)

So,

AB = AB

AD = BC

AC = BD

∠DAB = ∠CBA

∠DBA = ∠CAB

∠ADB = ∠BCA

Hope it helped and BELIEVING you UNDERSTOOD it....All the best



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