1.

Solve this and explain ​

Answer»

Answer:

Option D

Explanation:

Let the third spherical CONDUCTOR be A

Initial force=F=kq^2/r^2

When you touch A with B, total CHARGE present on B and A gets EQUALLY divided.

Total charge on both B and A =q+0=q

So after touching, charge on both

B and A=q/2

Now A is touched with C

Total charge on both A and C=q/2+q=3q/2

Now this total charge gets equally divided between A and C.

So after touching, charge on both

A and C=3q/4

Now charge on B =q/2

charge on C=3q/4

Force=3Kq^2/8r^2=3F/8



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