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Solve this and explain |
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Answer» Answer: Option D Explanation: Let the third spherical CONDUCTOR be A Initial force=F=kq^2/r^2 When you touch A with B, total CHARGE present on B and A gets EQUALLY divided. Total charge on both B and A =q+0=q So after touching, charge on both B and A=q/2 Now A is touched with C Total charge on both A and C=q/2+q=3q/2 Now this total charge gets equally divided between A and C. So after touching, charge on both A and C=3q/4 Now charge on B =q/2 charge on C=3q/4 Force=3Kq^2/8r^2=3F/8 |
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