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Solve these numericals:- (PLEASE HELP, URGENTLY NEEDED!) 1) A stone is dropped from a tall building of 80 metres height. Find its final velocity and the time taken to touch the ground (take g = 10 metres per second square). 2) A car initially at rest starts moving with an acceleration of 0.5 metres per second square and travels a distance of 25 metres. Calculate its final velocity and its time. |
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Answer» s = 80 m = displacement u = 0 = initial velocity g = 10 m/sec/sec acceleration of the STONE equation of motion : v² = u ² + 2 a s v² = 0 + 2 * 10 * 80 = 1600 v = final velocity = 40 m/sec2) u = 0 a = 0.50 m/sec/sec s = 25 m v² = u² + 2 a s = 0 + 2 * 0.4 * 25 = 20 v = √20 m /sec = 2 √5 m/s v = u + a t t = (v - u) / a = 2√5 / 0.50 = 4 √5 seconds. |
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