Solve the values of x in sin(x-32)=0for 0° is less than or equal to x

1.	Solve the values of x in sin(x-32)=0for 0° is less than or equal to x and is less than or equal to 180°
Answer» $\huge\mathcal{\underline{\color{aqua} Good\: Afternoon}}$ $\huge{\orange{\boxed{\fcolorbox{lime}{cadetblue}{\pink{ANSWER}}}}} \\$ $\red\checkmark\:\sin(<klux>X</klux> - <klux>32</klux>) = 0 \\ \\ = > \sin(x - 32) = \sin0 \\ \\ = > x - 32 = 0 \\ \\ = > x = 32$ ⭐ THEREFORE, the VALUE of x is 32 .

Solve the values of x in sin(x-32)=0for 0° is less than or equal to x and is less than or equal to 180°

Answer»

$\huge\mathcal{\underline{\color{aqua} Good\: Afternoon}}$

$\huge{\orange{\boxed{\fcolorbox{lime}{cadetblue}{\pink{ANSWER}}}}} \\$

$\red\checkmark\:\sin(<klux>X</klux> - <klux>32</klux>) = 0 \\ \\ = > \sin(x - 32) = \sin0 \\ \\ = > x - 32 = 0 \\ \\ = > x = 32$

⭐ THEREFORE, the VALUE of x is 32 .

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Solve the values of x in sin(x-32)=0for 0° is less than or equal to x and is less than or equal to 180°​

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Solve the values of x in sin(x-32)=0for 0° is less than or equal to x and is less than or equal to 180°