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Solve the question A.P |
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Answer» GIVEN term26 = 0 a+25d =0 --------(1st) term11 = 3 a+10d =3 ---------(2nd) SUBTRACT 2from 1, a+25d-a-10d =0-3 15d= -3 d= -3/15 = -1/5 PUT the VALUE of d in eq. 1st a=25÷(1/5) a=5 also I = -1/5 a+(n-1)d=-1/5 5+(n-1)(-1/5)=-1/5 5-1n/5+1/5 =-1/5 31/5+1/5=1n/5 32/5=1n/5 32/5*5=n n=32 Ihope that it will help you if any dot plz ask |
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