Solve the quadratic equation and give your answer correct to two decim

1.	Solve the quadratic equation and give your answer correct to two decimal places: 5(x+1)2 +10(x+1)+3=0. [√40=0.6325]
Answer» ✪ᴀɴsᴡᴇʀ✪ $\boxed{\bf{x = - 1.37, - 2.63}}$ ⍟ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ⍟ The equation can be solved as follows $\to 5(x+1)^2 + 10(x+1)+3=0$ For simplicity put $x+1 = y$ $\to 5y^2 +10y+3=0$ Using quadratic formula, $\to y = \frac{-10±\sqrt{10^2 - 4.5.3} }{2.5}$ $\to y = \frac{-10±\sqrt{100 - 60} }{10}$ $\to y = \frac{-10±\sqrt{40}}{10}$ $\to y = \frac{-10± 6.3246}{10}$ $\to y = \frac{-10+6.3246}{10}, \frac{-10-6.3246}{10}$ $\to y = \frac{-3.6754}{10}, \frac{-16.3246}{10}$ $\to y = - 0.36754, -1.63246$ $\to x+1 = - 0.36754, -1.63246$ $\to x = - 1 - 0.36754, - 1 -1.63246$ $\to x = - 1.36754, - 2.63246$ ROUNDING off to TWO DECIMAL places, we GET $\to x = - 1.37, - 2.63$