Solve the quadratic equation 4x²+ 12x+8 =0

1.	Solve the quadratic equation 4x²+ 12x+8 =0
Answer» Answer: 4x²+ 12x+8 =0 (22x2 - 12x) + 8 = 0 4X2 - 12x + 8 = 4 • (x2 - 3x + 2) Factoring x2 - 3x + 2 The first term is, x2 its COEFFICIENT is 1 . The MIDDLE term is, -3x its coefficient is -3 . The last term, "the CONSTANT", is +2 Step-1 : Multiply the coefficient of the first term by the constant 1 • 2 = 2 Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is -3 .

Answer»

Answer:

4x²+ 12x+8 =0

(22x2 - 12x) + 8 = 0

4X2 - 12x + 8 = 4 • (x2 - 3x + 2)

Factoring x2 - 3x + 2

The first term is, x2 its COEFFICIENT is 1 .

The MIDDLE term is, -3x its coefficient is -3 .

The last term, "the CONSTANT", is +2

Step-1 : Multiply the coefficient of the first term by the constant 1 • 2 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is -3 .

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Solve the quadratic equation 4x²+ 12x+8 =0​

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Solve the quadratic equation 4x²+ 12x+8 =0