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Solve the problem:\(3 \frac{4}{5} + 2 \frac{3}{10} + 1 \frac{1}{15}\) |
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Answer» First convert each mixed fraction into improper fraction. We get, \(\Rightarrow 3 \frac{4}{5} = \frac{19}{5}\) \(\Rightarrow 2 \frac{3}{10} = \frac{23}{10}\) \(\Rightarrow 1 \frac{1}{15} = \frac{16}{15}\) Then, \(\frac{19}{5} + \frac{23}{10} + \frac{16}{15}\) LCM of 5,10,15 = 30 Now,let us change each of the given fraction into an equivalent fraction having 30 as the denominator \(\Rightarrow \frac{19}{5} \times \frac{6}{6} = \frac{114}{30}\) \(\Rightarrow \frac{23}{10} \times \frac{3}{3} = \frac{69}{30}\) \(\Rightarrow \frac{16}{15} \times \frac{2}{2} = \frac{32}{30}\) Now, \(= \frac{114}{30} + \frac{69}{30} + \frac{32}{30}\) \(= \frac{114+69+32}{30}\) \(=\frac{215}{30}\) \(= 7 \frac{1}{5}\)
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