Solve the following systems of simultaneous linear equations by the me

1.	Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 11x + 15y = – 23, 7x – 2y = 20
Answer» The given equations are 11x + 15y = – 23 …(i) and 7x -2y = 20 …(ii) Multiplying (RBSESolutions.com) equation (i) by 2 and (ii) by 15 and then adding, we get 127x = 254 ⇒ x = 2 Putting x = 2 in (ii), we get 7 × 2 – 2y = 20 ⇒ 14 – 20 = 2y ⇒ 2y = – 6 ⇒ y = – 3 Hence the required solution is x = 2 and y = – 3.

Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 11x + 15y = – 23, 7x – 2y = 20

Answer»

The given equations are

11x + 15y = – 23 …(i)

and 7x -2y = 20 …(ii)

Multiplying (RBSESolutions.com) equation (i) by 2 and (ii) by 15 and then adding, we get

127x = 254

⇒ x = 2

Putting x = 2 in (ii), we get

7 × 2 – 2y = 20

⇒ 14 – 20 = 2y

⇒ 2y = – 6

⇒ y = – 3

Hence the required solution is x = 2 and y = – 3.