1.

Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 0.4x + 0.3y = 1.7, 0.7x – 0.2y = 0.8

Answer»

The given equations are

0.4x + 0.3y = 1.7 …(i)

0.7x – 0.2y = 0.8 …(ii)

Multiplying equation (i) by 2 and (ii) by 3 and then adding, we get

2.9x = 5.8

⇒ x = 2

Substituting the value of x in (i), we get

0.4 x 2 + 0.3y = 1.7

⇒ 0.3y = 1.7 – 0.8

⇒ 0.3y = 0.9

⇒ y = 3



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