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Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 0.4x + 0.3y = 1.7, 0.7x – 0.2y = 0.8 |
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Answer» The given equations are 0.4x + 0.3y = 1.7 …(i) 0.7x – 0.2y = 0.8 …(ii) Multiplying equation (i) by 2 and (ii) by 3 and then adding, we get 2.9x = 5.8 ⇒ x = 2 Substituting the value of x in (i), we get 0.4 x 2 + 0.3y = 1.7 ⇒ 0.3y = 1.7 – 0.8 ⇒ 0.3y = 0.9 ⇒ y = 3 |
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