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Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 2x + y = 13, 5x – 3y = 16 |
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Answer» The given equations are 2x + y = 13 …(i) and 5x – 3y= 16 …(ii) Multiplying equation (i) by 3 and then adding in (ii), we get 11x = 55 \(x=\frac { 55 }{ 11 }=5\) Substituting the value of x in (i), we get 2 × 5 + y = 13 ⇒ 10 + y = 13 ⇒ y = 13 – 10 = 3 Hence the required solution is x = 5, y = 3. |
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