1.

Solve the following systems of equations:\(\frac{x}{3}\)+\(\frac{y}{4}\) = 11\(\frac{5x}{6}\)- \(\frac{y}{3}\) = - 7

Answer»

 \(\frac{x}{3}\)+\(\frac{y}{4}\) = 11

⇒ 4x + 3y = 132

 \(\frac{5x}{6}\)\(\frac{y}{3}\) = - 7

⇒ 5x – 2y = -42

Multiplying eq1 by 2 and eq2 by 3 and adding them

⇒ 8x + 6y + 15x – 6y = 264 – 126

⇒ 23x = 138

⇒ x = 6

Thus,

24 + 3y = 132

⇒ y = 36



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