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Solve the following systems of equations:\(\frac{x}{3}\)+\(\frac{y}{4}\) = 11\(\frac{5x}{6}\)- \(\frac{y}{3}\) = - 7 |
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Answer» \(\frac{x}{3}\)+\(\frac{y}{4}\) = 11 ⇒ 4x + 3y = 132 \(\frac{5x}{6}\)- \(\frac{y}{3}\) = - 7 ⇒ 5x – 2y = -42 Multiplying eq1 by 2 and eq2 by 3 and adding them ⇒ 8x + 6y + 15x – 6y = 264 – 126 ⇒ 23x = 138 ⇒ x = 6 Thus, 24 + 3y = 132 ⇒ y = 36 |
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