Solve the following systems of equations:\(\frac{5}{x+1}\) - \(\frac

1.	Solve the following systems of equations:\(\frac{5}{x+1}\) - \(\frac{2}{y-1}\) = \(\frac{1}{2}\)\(\frac{10}{x+1}\) + \(\frac{2}{y-1}\) = \(\frac{5}{2}\)where, x ≠ -1, y ≠ 1
Answer» \(\frac{5}{x+1}\) - \(\frac{2}{y-1}\) = \(\frac{1}{2}\) \(\frac{10}{x+1}\) + \(\frac{2}{y-1}\) = \(\frac{5}{2}\) Adding eq1 and eq2 ⇒ 15/(x + 1) = 3 ⇒ x + 1 = 5 ⇒ x = 4 Thus, 5/5 – 2/(y – 1) = 12 ⇒ y – 1 = 4 ⇒ y = 5

Solve the following systems of equations:\(\frac{5}{x+1}\) - \(\frac{2}{y-1}\) = \(\frac{1}{2}\)\(\frac{10}{x+1}\) + \(\frac{2}{y-1}\) = \(\frac{5}{2}\)where, x ≠ -1, y ≠ 1

Answer»

\(\frac{5}{x+1}\) - \(\frac{2}{y-1}\) = \(\frac{1}{2}\)

\(\frac{10}{x+1}\) + \(\frac{2}{y-1}\) = \(\frac{5}{2}\)

Adding eq1 and eq2

⇒ 15/(x + 1) = 3

⇒ x + 1 = 5

⇒ x = 4

Thus,

5/5 – 2/(y – 1) = 12

⇒ y – 1 = 4

⇒ y = 5