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Solve the following systems of equations:\(\frac{22}{x+y}\)+\(\frac{15}{x-y}\) = 5\(\frac{55}{x+y}\)+\(\frac{45}{x-y}\) = 14 |
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Answer» \(\frac{22}{x+y}\)+\(\frac{15}{x-y}\) = 5 \(\frac{55}{x+y}\)+\(\frac{45}{x-y}\) = 14 Multiplying eq1 by 3 and subtracting from eq2 ⇒ - 11/(x + y) = - 1 ⇒ x + y = 11 ---------- (3) Multiplying eq1 by 5 and eq2 by 2 and subtracting ⇒ 15/(x – y) = 3 ⇒ x – y = 5 ------ (4) (3) + (4) ⇒ 2x = 16 ⇒ x = 8 Thus, y = 3 |
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