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Solve the following systems of equations:\(\frac{2}{x}\)+ \(\frac{5}{y}\) = 1\(\frac{60}{x}\)+\(\frac{40}{y}\) = 19, x ≠ 0, y ≠ 0 |
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Answer» \(\frac{2}{x}\)+ \(\frac{5}{y}\) = 1 \(\frac{60}{x}\)+\(\frac{40}{y}\) = 19, x ≠ 0, y ≠ 0 Multiplying eq1 by 8 and subtracting from eq2 ⇒ 44/x = 19 – 8 ⇒ x = 4 Thus, 2/4 + 5/y = 1 ⇒ 5/y = 1/2 ⇒ y = 10 |
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