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Solve the following systems of equations:\(\frac{1}{5x}\)+\(\frac{1}{6y}\) = 12\(\frac{1}{3x}\) - \(\frac{3}{7y}\) = 8, x ≠ 0, y ≠ 0 |
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Answer» \(\frac{1}{5x}\)+\(\frac{1}{6y}\) = 12 \(\frac{1}{3x}\) - \(\frac{3}{7y}\) = 8, x ≠ 0, y ≠ 0 Multiplying eq1 by 1/3 and eq2 by 1/5 and subtracting ⇒ 1/18y + 3/35y = 4 - 8/5 ⇒ 89/630y = 12/5 ⇒ y = 89/1512 Thus, 1/5x + 1512/534 = 12 ⇒ 1/5x = 816/89 ⇒ x = 89/4080 |
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