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Solve the following systems of equations:\(\frac{1}{2x}\)+\(\frac{1}{3y}\) = 2\(\frac{1}{3x}\)+\(\frac{1}{2y}\) = \(\frac{13}{6}\) |
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Answer» \(\frac{1}{2x}\)+\(\frac{1}{3y}\) = 2 \(\frac{1}{3x}\)+\(\frac{1}{2y}\) = \(\frac{13}{6}\) Multiplying eq 1 by 1/2 and eq2 by 1/3 and subtracting ⇒ 1/4x – 1/9x = 1 – 13/18 ⇒ 5/36x = 5/18 ⇒ x = 1/2 Thus, 1 + 1/3y = 2 ⇒ y = 1/3 |
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