Solve the following systems of equations:2x - \(\frac{3}{y}\) = 93x +

1.	Solve the following systems of equations:2x - \(\frac{3}{y}\) = 93x + \(\frac{7}{y}\) = 2, y ≠ 0
Answer» 2x - \(\frac{3}{y}\) = 9 3x + \(\frac{7}{y}\) = 2, y ≠ 0 Multiplying eq1 by 3 and eq2 by 2 and subtracting eq1 from eq2 ⇒ 6x + 21/y – 6x + 6/y = 4 – 27 ⇒ 23/y = - 23 ⇒ y = -1 Thus, 2x + 3 = 9 ⇒ x = 3

Solve the following systems of equations:2x - \(\frac{3}{y}\) = 93x + \(\frac{7}{y}\) = 2, y ≠ 0

Answer»

2x - \(\frac{3}{y}\) = 9

3x + \(\frac{7}{y}\) = 2, y ≠ 0

Multiplying eq1 by 3 and eq2 by 2 and subtracting eq1 from eq2

⇒ 6x + 21/y – 6x + 6/y = 4 – 27

⇒ 23/y = - 23

⇒ y = -1

Thus,

2x + 3 = 9

⇒ x = 3