Solve the following system of equations by elimination method: 2x +

1.	Solve the following system of equations by elimination method: 2x + 5y = 1; 2x + 3y = 3
Answer» Given pair of linear equations is 2x + 5y = 1 …(i) And 2x + 3y = 3 …(ii) On subtracting Eq. (ii) from Eq. (i), we get 2x + 3y – 2x – 5y = 3 – 1 ⇒ – 2y = 2 ⇒ y = – 1 On putting y = – 1 in Eq. (ii), we get 2x + 3( – 1) = 3 ⇒ 2x – 3 = 3 ⇒ 2x = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, x = 3 and y = – 1 , which is the required solution.

Solve the following system of equations by elimination method: 2x + 5y = 1; 2x + 3y = 3

Answer»

Given pair of linear equations is

2x + 5y = 1 …(i)

And 2x + 3y = 3 …(ii)

On subtracting Eq. (ii) from Eq. (i), we get

2x + 3y – 2x – 5y = 3 – 1

⇒ – 2y = 2

⇒ y = – 1

On putting y = – 1 in Eq. (ii), we get

2x + 3( – 1) = 3

⇒ 2x – 3 = 3

⇒ 2x = 6

⇒ x = 6/2

⇒ x = 3

Hence, x = 3 and y = – 1 , which is the required solution.