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Solve the following system of equations: 21/x +47/y = 11047/x +21/y = 162x, y ≠ 0 |
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Answer» Let 1/x = a and 1/y = b ⇒ 21a +47 b = 110 and 47a + 21b = 162 Adding and subtracting the two equations, we get a +b = 4 and a -b = 2 Solving the above two equations, we get a = 3 and b =1 ∴ x = 1/3 and y = 1 |
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