1.

Solve the following system of equations: 21/x +47/y = 11047/x +21/y = 162x, y ≠ 0

Answer»

Let 1/x = a and 1/y = b

⇒ 21a +47 b = 110 and 47a + 21b = 162

Adding and subtracting the two equations, 

we get a +b = 4 and a -b = 2

Solving the above two equations, we get a = 3 and b =1

∴ x = 1/3 and y = 1



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