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Solve the following quadratic equations by factorization method: x2 + (1 – 2i)x – 2i = 0 |
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Answer» x2 + (1 – 2i)x – 2i = 0 Given x2 + (1 – 2i)x – 2i = 0 ⇒ x2 + x – 2ix – 2i = 0 ⇒ x(x + 1) – 2i(x + 1) = 0 ⇒ (x + 1)(x – 2i) = 0 ⇒ x + 1 = 0 or x – 2i = 0 ∴ x = –1 or 2i Thus, the roots of the given equation are –1 and 2i. |
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