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Solve the following quadratic equations by factorization:\(16x-\frac{10}{x}=27\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(16x-\frac{10}{x}=27\) ⇒ 16x2 – 27x – 10 = 0 ⇒ 16x2 – 32x + 5x – 10 = 0 ⇒ 16x(x – 2) + 5(x – 2) = 0 ⇒ (16x + 5)(x – 2) = 0 ⇒ x = -5/16, 2 |
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