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Solve the following quadratic equations by factorization:\(\sqrt{2}x^{2}-3x-2\sqrt{2}= 0\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\sqrt{2}x^{2}-3x-2\sqrt{2}=0\) ⇒ √2x2 – 4x + x – 2√2 = 0 ⇒ √2x(x – 2√2) + (x – 2√2) = 0 ⇒ (√2x + 1)(x – 2√2) = 0 ⇒ x = -1/√2, 2√2 |
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