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Solve the following quadratic equations by factorization:\(6x^{2}+11x+3= 0\) |
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Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(6x^{2}+11x+3=0\) ⇒ 6x2 + 9x + 2x + 3 = 0 ⇒ 3x(2x + 3) + (2x + 3) = 0 ⇒ (3x + 1)(2x + 3) = 0 ⇒ x = -1/3, - 3/2 |
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